#3
Jika titik P(-3, 2), Q(6, 8), dan R adalah titik tengah PQ, maka persamaan garis yang tegak lurus dengan PQ dan melalui R adalah .....
- 2x – 3y + 12 = 0
- 2x – 3y – 19 = 0
- 6x – 4y + 13 = 0
- 6x + 4y + 21 = 0
- 6x + 4y – 29 = 0
Menurut Saya ...
Pendapat Teman
juan
E
E
D
D
Ivan Arsyaditya Pran
e
Jihan Nahda
C
Jihan Nahda
A
bias feny
m1=y2-y1/x2-x1
=8-2/6+3 = 2/3
m1m2=-1
2/3.m2=-1
m2=-3/2
y-y1/y2-y1=x-x1/x2-x1
y-2/8-2=x+3/6+3
y-2/6=x+3/9
y-2/2=x+3/3
dikali silang
3y-6=2x+6
-2x+3y-12=0
dikali -1
2x-3y+12=0 (A)
Nasrah
A. 2x -3y + 12=0
Maya
A
lulus ptn 21
titik tengah (R) = 3/2, 5
m PQ ( m1) = 2/3
tegak lurus, maka m2 = -3/2
PGS yg melalui R
y-y1 = m (x-x1)
y-5 = -3/2 (x+3/2)
kali 4
4y-20 = -6x+9
6x+4y-20-9 = 0
6x+4y-29 = 0 (D)
bantu koreksi ya temen2 :)
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